tolong di jawab ya kak
`Fungsi kuadrat
» (x + 5)² = 36
» (x + 5)(x + 5) = 36
» x(x + 5) + 5(x + 5) = 36
» x² + 5x + 5x + 25 = 36
» x² + 10x + 25 = 36
» x² + 10x + 25 - 36 = 0
» x² + 10x - 11 = 0
» (x + 11)(x - 1) = 0
» x + 11 = 0 or x - 1 = 0
» x = 0 - 11 or x = 0 + 1
» x = -11 or x = 1
Jadi, akar-akar nya yaitu x = -11 dan x = 1
Jawaban:
1 atau -11
Penjelasan :
Cara Melengkapkan kuadrat sempurna :
[tex] {(x + 5)}^{2} = 36 \\ \\ (x + 5) = \frac{ + }{ - } \sqrt{36} \\ \\ x = - 5 \frac{ + }{ - } 6 \\ \\ x = 1 \: atau \: - 11[/tex]
Cara Pemfaktoran :
[tex] {(x + 5)}^{2} = 36 \\ \\ ( {x}^{2} + 2 \times 5 \times x + {5}^{2} ) = 36 \\ \\ {x}^{2} + 10x + 25 = 36 \\ \\ {x}^{2} + 10x + 25 - 36 = 0 \\ \\ {x}^{2} + 10x - 11 = 0 \\ \\ \: (x + 11)(x - 1) = 0 \\ \\ x = 1 \: \: atau \: - 11[/tex]
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